If the locus of the points which are equidistant from point P and Q meets line PQ at point N, then PN equals
- A.
NQ - B.^{1}/_{4}NQ
- C.
2NQ - D.^{1}/_{2}NQ
Correct Answer: Option A
Explanation
Locus of point equidistant from points P and Q is a perpendicular bisector of the straight joining P and Q
∴PN = NQ